6x+(3x-7)=x+(4x-1)

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Solution for 6x+(3x-7)=x+(4x-1) equation: 



6x+(3x-7)=x+(4x-1)

We move all terms to the left:

6x+(3x-7)-(x+(4x-1))=0

We get rid of parentheses

6x+3x-(x+(4x-1))-7=0



We calculate terms in parentheses: -(x+(4x-1)), so:

x+(4x-1)

We get rid of parentheses

x+4x-1

We add all the numbers together, and all the variables

5x-1

Back to the equation:

-(5x-1)



We add all the numbers together, and all the variables

9x-(5x-1)-7=0

We get rid of parentheses

9x-5x+1-7=0

We add all the numbers together, and all the variables

4x-6=0

We move all terms containing x to the left, all other terms to the right

4x=6

x=6/4

x=1+1/2

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