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6x(4+1/3)=26
We move all terms to the left:
6x(4+1/3)-(26)=0
We add all the numbers together, and all the variables
6x(1/3+4)-26=0
We multiply parentheses
6x^2+24x-26=0
a = 6; b = 24; c = -26;
Δ = b2-4ac
Δ = 242-4·6·(-26)
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-20\sqrt{3}}{2*6}=\frac{-24-20\sqrt{3}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+20\sqrt{3}}{2*6}=\frac{-24+20\sqrt{3}}{12} $
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