1/4(12x-8)=19x+10-12

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Solution for 1/4(12x-8)=19x+10-12 equation: 



1/4(12x-8)=19x+10-12

We move all terms to the left:

1/4(12x-8)-(19x+10-12)=0



Domain of the equation: 4(12x-8)!=0

x∈R



We add all the numbers together, and all the variables

1/4(12x-8)-(19x-2)=0

We get rid of parentheses

1/4(12x-8)-19x+2=0

We multiply all the terms by the denominator


-19x*4(12x-8)+2*4(12x-8)+1=0

Wy multiply elements

-76x^2(1+8x(1+1=0

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