6x(3x+4)=x-40

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Solution for 6x(3x+4)=x-40 equation: 



6x(3x+4)=x-40

We move all terms to the left:

6x(3x+4)-(x-40)=0

We multiply parentheses

18x^2+24x-(x-40)=0

We get rid of parentheses

18x^2+24x-x+40=0

We add all the numbers together, and all the variables

18x^2+23x+40=0

a = 18; b = 23; c = +40;
Δ = b2-4ac
Δ = 232-4·18·40
Δ = -2351
Delta is less than zero, so there is no solution for the equation

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