6x(2x-2)=7x(-2x-4)

Solution for 6x(2x-2)=7x(-2x-4) equation:

6x(2x-2)=7x(-2x-4)

We move all terms to the left:

6x(2x-2)-(7x(-2x-4))=0

We multiply parentheses

12x^2-12x-(7x(-2x-4))=0


We calculate terms in parentheses: -(7x(-2x-4)), so:

7x(-2x-4)

We multiply parentheses

-14x^2-28x

Back to the equation:

-(-14x^2-28x)


We get rid of parentheses

12x^2+14x^2+28x-12x=0

We add all the numbers together, and all the variables

26x^2+16x=0

a = 26; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·26·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*26}=\frac{-32}{52}
=-8/13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*26}=\frac{0}{52}
=0
$