(y+4)=4(y+3)-y

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Solution for (y+4)=4(y+3)-y equation: 



(y+4)=4(y+3)-y

We move all terms to the left:

(y+4)-(4(y+3)-y)=0

We get rid of parentheses

y-(4(y+3)-y)+4=0



We calculate terms in parentheses: -(4(y+3)-y), so:

4(y+3)-y

We add all the numbers together, and all the variables

-1y+4(y+3)

We multiply parentheses

-1y+4y+12

We add all the numbers together, and all the variables

3y+12

Back to the equation:

-(3y+12)



We get rid of parentheses

y-3y-12+4=0

We add all the numbers together, and all the variables

-2y-8=0

We move all terms containing y to the left, all other terms to the right

-2y=8

y=8/-2

y=-4

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