6v-2+2(4v+3)=-2(v+3)

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Solution for 6v-2+2(4v+3)=-2(v+3) equation: 



6v-2+2(4v+3)=-2(v+3)

We move all terms to the left:

6v-2+2(4v+3)-(-2(v+3))=0

We multiply parentheses

6v+8v-(-2(v+3))+6-2=0



We calculate terms in parentheses: -(-2(v+3)), so:

-2(v+3)

We multiply parentheses

-2v-6

Back to the equation:

-(-2v-6)



We add all the numbers together, and all the variables

14v-(-2v-6)+4=0

We get rid of parentheses

14v+2v+6+4=0

We add all the numbers together, and all the variables

16v+10=0

We move all terms containing v to the left, all other terms to the right

16v=-10

v=-10/16

v=-5/8

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