3(n-2)+4(n+1)=29

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Solution for 3(n-2)+4(n+1)=29 equation: 



3(n-2)+4(n+1)=29

We move all terms to the left:

3(n-2)+4(n+1)-(29)=0

We multiply parentheses

3n+4n-6+4-29=0

We add all the numbers together, and all the variables

7n-31=0

We move all terms containing n to the left, all other terms to the right

7n=31

n=31/7

n=4+3/7

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