6u-6+2(2u+3)=-4(u+1)

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Solution for 6u-6+2(2u+3)=-4(u+1) equation: 



6u-6+2(2u+3)=-4(u+1)

We move all terms to the left:

6u-6+2(2u+3)-(-4(u+1))=0

We multiply parentheses

6u+4u-(-4(u+1))+6-6=0



We calculate terms in parentheses: -(-4(u+1)), so:

-4(u+1)

We multiply parentheses

-4u-4

Back to the equation:

-(-4u-4)



We add all the numbers together, and all the variables

10u-(-4u-4)=0

We get rid of parentheses

10u+4u+4=0

We add all the numbers together, and all the variables

14u+4=0

We move all terms containing u to the left, all other terms to the right

14u=-4

u=-4/14

u=-2/7

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