3(y+5)=-9y+39

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Solution for 3(y+5)=-9y+39 equation: 



3(y+5)=-9y+39

We move all terms to the left:

3(y+5)-(-9y+39)=0

We multiply parentheses

3y-(-9y+39)+15=0

We get rid of parentheses

3y+9y-39+15=0

We add all the numbers together, and all the variables

12y-24=0

We move all terms containing y to the left, all other terms to the right

12y=24

y=24/12

y=2

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