6u+2-4(-2u-3)=4(u-1)

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Solution for 6u+2-4(-2u-3)=4(u-1) equation: 



6u+2-4(-2u-3)=4(u-1)

We move all terms to the left:

6u+2-4(-2u-3)-(4(u-1))=0

We multiply parentheses

6u+8u-(4(u-1))+12+2=0



We calculate terms in parentheses: -(4(u-1)), so:

4(u-1)

We multiply parentheses

4u-4

Back to the equation:

-(4u-4)



We add all the numbers together, and all the variables

14u-(4u-4)+14=0

We get rid of parentheses

14u-4u+4+14=0

We add all the numbers together, and all the variables

10u+18=0

We move all terms containing u to the left, all other terms to the right

10u=-18

u=-18/10

u=-1+4/5

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