6t+8/9t-7=2t+3/3t-5

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Solution for 6t+8/9t-7=2t+3/3t-5 equation: 



6t+8/9t-7=2t+3/3t-5

We move all terms to the left:

6t+8/9t-7-(2t+3/3t-5)=0



Domain of the equation: 9t!=0

t!=0/9

t!=0

t∈R





Domain of the equation: 3t-5)!=0

t∈R



We get rid of parentheses

6t+8/9t-2t-3/3t+5-7=0

We calculate fractions


6t-2t+24t/27t^2+(-27t)/27t^2+5-7=0

We add all the numbers together, and all the variables

4t+24t/27t^2+(-27t)/27t^2-2=0

We multiply all the terms by the denominator


4t*27t^2+24t+(-27t)-2*27t^2=0

We add all the numbers together, and all the variables

24t+4t*27t^2+(-27t)-2*27t^2=0

Wy multiply elements

108t^3-54t^2+24t+(-27t)=0

We get rid of parentheses

108t^3-54t^2+24t-27t=0

We do not support etpression: t^3

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