(2x-1)2-4x(2-1)=3(2x-1)

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Solution for (2x-1)2-4x(2-1)=3(2x-1) equation: 



(2x-1)2-4x(2-1)=3(2x-1)

We move all terms to the left:

(2x-1)2-4x(2-1)-(3(2x-1))=0

We add all the numbers together, and all the variables

(2x-1)2-4x1-(3(2x-1))=0

We add all the numbers together, and all the variables

-4x+(2x-1)2-(3(2x-1))=0

We multiply parentheses

-4x+4x-(3(2x-1))-2=0



We calculate terms in parentheses: -(3(2x-1)), so:

3(2x-1)

We multiply parentheses

6x-3

Back to the equation:

-(6x-3)



We add all the numbers together, and all the variables

-(6x-3)-2=0

We get rid of parentheses

-6x+3-2=0

We add all the numbers together, and all the variables

-6x+1=0

We move all terms containing x to the left, all other terms to the right

-6x=-1

x=-1/-6

x=1/6

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