6s-4=(2+1/4s)

Solution for 6s-4=(2+1/4s) equation:

6s-4=(2+1/4s)

We move all terms to the left:

6s-4-((2+1/4s))=0


Domain of the equation: 4s))!=0

s!=0/1

s!=0

s∈R


We add all the numbers together, and all the variables

6s-((1/4s+2))-4=0

We multiply all the terms by the denominator


6s*4s-4*4s+2))-((1+2))=0

We add all the numbers together, and all the variables

6s*4s-4*4s+2))-(3)=0

We add all the numbers together, and all the variables

6s*4s-4*4s=0

Wy multiply elements

24s^2-16s=0

a = 24; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·24·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*24}=\frac{0}{48}
=0
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*24}=\frac{32}{48}
=2/3
$