6r+2(2r+4)=2(r-2)-4

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Solution for 6r+2(2r+4)=2(r-2)-4 equation: 



6r+2(2r+4)=2(r-2)-4

We move all terms to the left:

6r+2(2r+4)-(2(r-2)-4)=0

We multiply parentheses

6r+4r-(2(r-2)-4)+8=0



We calculate terms in parentheses: -(2(r-2)-4), so:

2(r-2)-4

We multiply parentheses

2r-4-4

We add all the numbers together, and all the variables

2r-8

Back to the equation:

-(2r-8)



We add all the numbers together, and all the variables

10r-(2r-8)+8=0

We get rid of parentheses

10r-2r+8+8=0

We add all the numbers together, and all the variables

8r+16=0

We move all terms containing r to the left, all other terms to the right

8r=-16

r=-16/8

r=-2

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