(x-4)/5=(2x+3)/6

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Solution for (x-4)/5=(2x+3)/6 equation: 



(x-4)/5=(2x+3)/6

We move all terms to the left:

(x-4)/5-((2x+3)/6)=0

We calculate fractions


x/()+(-((2x+3)*5)/()=0



We calculate terms in parentheses: +(-((2x+3)*5)/(), so:

-((2x+3)*5)/(

We multiply all the terms by the denominator


-((2x+3)*5)



We calculate terms in parentheses: -((2x+3)*5), so:

(2x+3)*5

We multiply parentheses

10x+15

Back to the equation:

-(10x+15)



We get rid of parentheses

-10x-15

Back to the equation:

+(-10x-15)



We get rid of parentheses

x/()-10x-15=0

We multiply all the terms by the denominator


x-10x*()-15*()=0

We add all the numbers together, and all the variables

x-10x*()=0

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