6n-3n*2n+n=9(n*n)

Solution for 6n-3n*2n+n=9(n*n) equation:

6n-3n*2n+n=9(n*n)

We move all terms to the left:

6n-3n*2n+n-(9(n*n))=0

We add all the numbers together, and all the variables

6n-3n*2n+n-(9(+n*n))=0

We add all the numbers together, and all the variables

7n-3n*2n-(9(+n*n))=0

Wy multiply elements

-6n^2+7n-(9(+n*n))=0


We calculate terms in parentheses: -(9(+n*n)), so:

9(+n*n)

We multiply parentheses

9n^2

Back to the equation:

-(9n^2)


determiningTheFunctionDomain
-6n^2-9n^2+7n=0

We add all the numbers together, and all the variables

-15n^2+7n=0

a = -15; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-15)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-15}=\frac{-14}{-30}
=7/15
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-15}=\frac{0}{-30}
=0
$