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3a(-8a)=-99
We move all terms to the left:
3a(-8a)-(-99)=0
We add all the numbers together, and all the variables
3a(-8a)+99=0
We multiply parentheses
-24a^2+99=0
a = -24; b = 0; c = +99;
Δ = b2-4ac
Δ = 02-4·(-24)·99
Δ = 9504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9504}=\sqrt{144*66}=\sqrt{144}*\sqrt{66}=12\sqrt{66}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{66}}{2*-24}=\frac{0-12\sqrt{66}}{-48} =-\frac{12\sqrt{66}}{-48} =-\frac{\sqrt{66}}{-4} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{66}}{2*-24}=\frac{0+12\sqrt{66}}{-48} =\frac{12\sqrt{66}}{-48} =\frac{\sqrt{66}}{-4} $
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