6n+35=4+7(3n-2)

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Solution for 6n+35=4+7(3n-2) equation: 



6n+35=4+7(3n-2)

We move all terms to the left:

6n+35-(4+7(3n-2))=0



We calculate terms in parentheses: -(4+7(3n-2)), so:

4+7(3n-2)

determiningTheFunctionDomain
7(3n-2)+4

We multiply parentheses

21n-14+4

We add all the numbers together, and all the variables

21n-10

Back to the equation:

-(21n-10)



We get rid of parentheses

6n-21n+10+35=0

We add all the numbers together, and all the variables

-15n+45=0

We move all terms containing n to the left, all other terms to the right

-15n=-45

n=-45/-15

n=+3

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