8=-3(1-x)+4(x+1)

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Solution for 8=-3(1-x)+4(x+1) equation: 



8=-3(1-x)+4(x+1)

We move all terms to the left:

8-(-3(1-x)+4(x+1))=0

We add all the numbers together, and all the variables

-(-3(-1x+1)+4(x+1))+8=0



We calculate terms in parentheses: -(-3(-1x+1)+4(x+1)), so:

-3(-1x+1)+4(x+1)

We multiply parentheses

3x+4x-3+4

We add all the numbers together, and all the variables

7x+1

Back to the equation:

-(7x+1)



We get rid of parentheses

-7x-1+8=0

We add all the numbers together, and all the variables

-7x+7=0

We move all terms containing x to the left, all other terms to the right

-7x=-7

x=-7/-7

x=1

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