6m(3m+21)=9(

Solution for 6m(3m+21)=9( equation:

6m(3m+21)=9(

We move all terms to the left:

6m(3m+21)-(9()=0

We add all the numbers together, and all the variables

6m(3m+21)=0

We multiply parentheses

18m^2+126m=0

a = 18; b = 126; c = 0;
Δ = b2-4ac
Δ = 1262-4·18·0
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-126}{2*18}=\frac{-252}{36}
=-7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+126}{2*18}=\frac{0}{36}
=0
$