6k-12=3(2k-4)

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Solution for 6k-12=3(2k-4) equation: 



6k-12=3(2k-4)

We move all terms to the left:

6k-12-(3(2k-4))=0



We calculate terms in parentheses: -(3(2k-4)), so:

3(2k-4)

We multiply parentheses

6k-12

Back to the equation:

-(6k-12)



We get rid of parentheses

6k-6k+12-12=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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