1=8t(-2t+1)

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Solution for 1=8t(-2t+1) equation:



1=8t(-2t+1)
We move all terms to the left:
1-(8t(-2t+1))=0
We calculate terms in parentheses: -(8t(-2t+1)), so:
8t(-2t+1)
We multiply parentheses
-16t^2+8t
Back to the equation:
-(-16t^2+8t)
We get rid of parentheses
16t^2-8t+1=0
a = 16; b = -8; c = +1;
Δ = b2-4ac
Δ = -82-4·16·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{8}{32}=1/4$

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