6k-(3+k)=-(2k+3)

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Solution for 6k-(3+k)=-(2k+3) equation: 



6k-(3+k)=-(2k+3)

We move all terms to the left:

6k-(3+k)-(-(2k+3))=0

We add all the numbers together, and all the variables

6k-(k+3)-(-(2k+3))=0

We get rid of parentheses

6k-k-(-(2k+3))-3=0



We calculate terms in parentheses: -(-(2k+3)), so:

-(2k+3)

We get rid of parentheses

-2k-3

Back to the equation:

-(-2k-3)



We add all the numbers together, and all the variables

5k-(-2k-3)-3=0

We get rid of parentheses

5k+2k+3-3=0

We add all the numbers together, and all the variables

7k=0

k=0/7

k=0

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