6c+7(c-11)=4c-3(c-10)

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Solution for 6c+7(c-11)=4c-3(c-10) equation: 



6c+7(c-11)=4c-3(c-10)

We move all terms to the left:

6c+7(c-11)-(4c-3(c-10))=0

We multiply parentheses

6c+7c-(4c-3(c-10))-77=0



We calculate terms in parentheses: -(4c-3(c-10)), so:

4c-3(c-10)

We multiply parentheses

4c-3c+30

We add all the numbers together, and all the variables

c+30

Back to the equation:

-(c+30)



We add all the numbers together, and all the variables

13c-(c+30)-77=0

We get rid of parentheses

13c-c-30-77=0

We add all the numbers together, and all the variables

12c-107=0

We move all terms containing c to the left, all other terms to the right

12c=107

c=107/12

c=8+11/12

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