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(5x+7)(2x-5)=0
We multiply parentheses ..
(+10x^2-25x+14x-35)=0
We get rid of parentheses
10x^2-25x+14x-35=0
We add all the numbers together, and all the variables
10x^2-11x-35=0
a = 10; b = -11; c = -35;
Δ = b2-4ac
Δ = -112-4·10·(-35)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-39}{2*10}=\frac{-28}{20} =-1+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+39}{2*10}=\frac{50}{20} =2+1/2 $
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