6c+40=4c+200

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Solution for 6c+40=4c+200 equation: 



6c+40=4c+200

We move all terms to the left:

6c+40-(4c+200)=0

We get rid of parentheses

6c-4c-200+40=0

We add all the numbers together, and all the variables

2c-160=0

We move all terms containing c to the left, all other terms to the right

2c=160

c=160/2

c=80

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