3y-1=7-(y+4)

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Solution for 3y-1=7-(y+4) equation: 



3y-1=7-(y+4)

We move all terms to the left:

3y-1-(7-(y+4))=0



We calculate terms in parentheses: -(7-(y+4)), so:

7-(y+4)

determiningTheFunctionDomain
-(y+4)+7

We get rid of parentheses

-y-4+7

We add all the numbers together, and all the variables

-1y+3

Back to the equation:

-(-1y+3)



We get rid of parentheses

3y+1y-3-1=0

We add all the numbers together, and all the variables

4y-4=0

We move all terms containing y to the left, all other terms to the right

4y=4

y=4/4

y=1

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