6b-4(3+5b)=58

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Solution for 6b-4(3+5b)=58 equation: 



6b-4(3+5b)=58

We move all terms to the left:

6b-4(3+5b)-(58)=0

We add all the numbers together, and all the variables

6b-4(5b+3)-58=0

We multiply parentheses

6b-20b-12-58=0

We add all the numbers together, and all the variables

-14b-70=0

We move all terms containing b to the left, all other terms to the right

-14b=70

b=70/-14

b=-5

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