(3/5)+(1/7x)-(1/3)=(6/7x)

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Solution for (3/5)+(1/7x)-(1/3)=(6/7x) equation: 



(3/5)+(1/7x)-(1/3)=(6/7x)

We move all terms to the left:

(3/5)+(1/7x)-(1/3)-((6/7x))=0



Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 7x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/7x)-((+6/7x))+(+3/5)-(+1/3)=0

We get rid of parentheses

1/7x-((+6/7x))+3/5-1/3=0

We calculate fractions


(-((+6*7x*5*3)/735x^2+3087x^2/735x^2+(-1715x^2)/735x^2+105x/735x^2=0

We can not solve this equation

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