6b-24/(b+3)(b-7)=0

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Solution for 6b-24/(b+3)(b-7)=0 equation: 


D( b )

b+3 = 0

b+3 = 0

b+3 = 0

b+3 = 0 // - 3

b = -3

b in (-oo:-3) U (-3:+oo)

6*b-((24/(b+3))*(b-7)) = 0

6*b-24*(b+3)^-1*(b-7) = 0

(-24*(b-7))/(b+3)+6*b = 0

(-24*(b-7))/(b+3)+(6*b*(b+3))/(b+3) = 0

6*b*(b+3)-24*(b-7) = 0

6*b^2-6*b+168 = 0

6*b^2-6*b+168 = 0

6*(b^2-b+28) = 0

b^2-b+28 = 0

DELTA = (-1)^2-(1*4*28)

DELTA = -111

DELTA < 0

6 = 0

6/(b+3) = 0

6/(b+3) = 0 // * b+3

6 = 0

b belongs to the empty set

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