(2/x+1)(3/x-1)=4

Solution for (2/x+1)(3/x-1)=4 equation:

D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2/x+1)*(3/x-1) = 4 // - 4

(2/x+1)*(3/x-1)-4 = 0

(2*x^-1+1)*(3*x^-1-1)-4 = 0

(2*x^-1+1)*(3*x^-1-1)-4 = 0

x^-1+6*x^-2-5 = 0

x^-1+6*x^-2-5 = 0

1*x^-1+6*x^-2-5*x^0 = 0

(1*x^1-5*x^2+6*x^0)/(x^2) = 0 // * x^4

x^2*(1*x^1-5*x^2+6*x^0) = 0

x^2

x-5*x^2+6 = 0

x-5*x^2+6 = 0

DELTA = 1^2-(-5*4*6)

DELTA = 121

DELTA > 0

x = (121^(1/2)-1)/(-5*2) or x = (-121^(1/2)-1)/(-5*2)

x = -1 or x = 6/5

x in { -1, 6/5} 

(x+1)*(x-6/5) = 0

(x+1)*(x-6/5) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-6/5 )

x-6/5 = 0 // + 6/5

x = 6/5

x in { -1, 6/5 }