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6a^2+7a-10=0
a = 6; b = 7; c = -10;
Δ = b2-4ac
Δ = 72-4·6·(-10)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-17}{2*6}=\frac{-24}{12} =-2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+17}{2*6}=\frac{10}{12} =5/6 $
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