(7a+6)/4=(2a-3)/5

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Solution for (7a+6)/4=(2a-3)/5 equation: 



(7a+6)/4=(2a-3)/5

We move all terms to the left:

(7a+6)/4-((2a-3)/5)=0

We calculate fractions


7a/()+(-((2a-3)*4)/()=0



We calculate terms in parentheses: +(-((2a-3)*4)/(), so:

-((2a-3)*4)/(

We multiply all the terms by the denominator


-((2a-3)*4)



We calculate terms in parentheses: -((2a-3)*4), so:

(2a-3)*4

We multiply parentheses

8a-12

Back to the equation:

-(8a-12)



We get rid of parentheses

-8a+12

Back to the equation:

+(-8a+12)



We get rid of parentheses

7a/()-8a+12=0

We multiply all the terms by the denominator


7a-8a*()+12*()=0

We add all the numbers together, and all the variables

7a-8a*()=0

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