(3x+1)=2(3x+5)

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Solution for (3x+1)=2(3x+5) equation:



(3x+1)=2(3x+5)
We move all terms to the left:
(3x+1)-(2(3x+5))=0
We get rid of parentheses
3x-(2(3x+5))+1=0
We calculate terms in parentheses: -(2(3x+5)), so:
2(3x+5)
We multiply parentheses
6x+10
Back to the equation:
-(6x+10)
We get rid of parentheses
3x-6x-10+1=0
We add all the numbers together, and all the variables
-3x-9=0
We move all terms containing x to the left, all other terms to the right
-3x=9
x=9/-3
x=-3

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