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6a(2a+3)=0
We multiply parentheses
12a^2+18a=0
a = 12; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·12·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*12}=\frac{-36}{24} =-1+1/2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*12}=\frac{0}{24} =0 $
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