(4y+7=2y-1)

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Solution for (4y+7=2y-1) equation: 



(4y+7=2y-1)

We move all terms to the left:

(4y+7-(2y-1))=0



We calculate terms in parentheses: +(4y+7-(2y-1)), so:

4y+7-(2y-1)

determiningTheFunctionDomain
4y-(2y-1)+7

We get rid of parentheses

4y-2y+1+7

We add all the numbers together, and all the variables

2y+8

Back to the equation:

+(2y+8)



We get rid of parentheses

2y+8=0

We move all terms containing y to the left, all other terms to the right

2y=-8

y=-8/2

y=-4

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