6=b-83/2

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Solution for 6=b-83/2 equation: 



6=b-83/2

We move all terms to the left:

6-(b-83/2)=0

We add all the numbers together, and all the variables

-(+b-83/2)+6=0

We get rid of parentheses

-b+6+83/2=0

We multiply all the terms by the denominator


-b*2+83+6*2=0

We add all the numbers together, and all the variables

-b*2+95=0

Wy multiply elements

-2b+95=0

We move all terms containing b to the left, all other terms to the right

-2b=-95

b=-95/-2

b=47+1/2

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