10(4x-5)=20x+50

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Solution for 10(4x-5)=20x+50 equation: 



10(4x-5)=20x+50

We move all terms to the left:

10(4x-5)-(20x+50)=0

We multiply parentheses

40x-(20x+50)-50=0

We get rid of parentheses

40x-20x-50-50=0

We add all the numbers together, and all the variables

20x-100=0

We move all terms containing x to the left, all other terms to the right

20x=100

x=100/20

x=5

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