6=5(c+2.2)+10

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Solution for 6=5(c+2.2)+10 equation: 



6=5(c+2.2)+10

We move all terms to the left:

6-(5(c+2.2)+10)=0



We calculate terms in parentheses: -(5(c+2.2)+10), so:

5(c+2.2)+10

We multiply parentheses

5c+11+10

We add all the numbers together, and all the variables

5c+21

Back to the equation:

-(5c+21)



We get rid of parentheses

-5c-21+6=0

We add all the numbers together, and all the variables

-5c-15=0

We move all terms containing c to the left, all other terms to the right

-5c=15

c=15/-5

c=-3

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