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6(x-4)/2=3(x+1/6
We move all terms to the left:
6(x-4)/2-(3(x+1/6)=0
We add all the numbers together, and all the variables
6(x-4)/2-(3(+x+1/6)=0
We calculate fractions
6x/()+(-(3(+x+1*2)/()=0
We calculate terms in parentheses: +(-(3(+x+1*2)/(), so:
-(3(+x+1*2)/(
We add all the numbers together, and all the variables
-(3(x+2)/(
We multiply all the terms by the denominator
-(3(x+2)
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3(x+2
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3(x+2
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3(x+2
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3(x+2
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3(x+2
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3(x+2
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3(x+2
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3(x+2
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3(x+2
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3(x+2
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3(x+2
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See similar equations:
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