6=2/7(2x+28

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Solution for 6=2/7(2x+28 equation: 



6=2/7(2x+28

We move all terms to the left:

6-(2/7(2x+28)=0



Domain of the equation: 7(2x+28)+6!=0

We move all terms containing x to the left, all other terms to the right

7(2x+28)!=-6

x∈R



We multiply all the terms by the denominator


-(2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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