(-1/3)(x-9)=-1

Solution for (-1/3)(x-9)=-1 equation:

(-1/3)(x-9)=-1

We move all terms to the left:

(-1/3)(x-9)-(-1)=0


Domain of the equation: 3)(x-9)!=0

x∈R


We add all the numbers together, and all the variables

(-1/3)(x-9)+1=0

We multiply parentheses ..

(-1x^2-1/3*-9)+1=0

We multiply all the terms by the denominator


(-1x^2-1+1*3*-9)=0

We get rid of parentheses

-1x^2-1-9+1*3*=0

We add all the numbers together, and all the variables

-1x^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-2}=0$