6=(4/5)(0)+b

Solution for 6=(4/5)(0)+b equation:

6=(4/5)(0)+b

We move all terms to the left:

6-((4/5)(0)+b)=0


Domain of the equation: 5)0+b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

-((+4/5)0+b)+6=0

We multiply all the terms by the denominator


-((+4+6*5)0+b)=0


We calculate terms in parentheses: -((+4+6*5)0+b), so:

(+4+6*5)0+b

determiningTheFunctionDomain
b+(+4+6*5)0

We add all the numbers together, and all the variables

b+340

Back to the equation:

-(b+340)


We get rid of parentheses

-b-340=0

We add all the numbers together, and all the variables

-1b-340=0

We move all terms containing b to the left, all other terms to the right

-b=340

b=340/-1

b=-340