10=(-1/3)(-6)+b

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Solution for 10=(-1/3)(-6)+b equation: 



10=(-1/3)(-6)+b

We move all terms to the left:

10-((-1/3)(-6)+b)=0



Domain of the equation: 3)(-6)+b)!=0

b∈R



We multiply parentheses ..

-(2+b)+10=0

We add all the numbers together, and all the variables

-(b+2)+10=0

We get rid of parentheses

-b-2+10=0

We add all the numbers together, and all the variables

-1b+8=0

We move all terms containing b to the left, all other terms to the right

-b=-8

b=-8/-1

b=+8

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