6=(3x+1)2

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Solution for 6=(3x+1)2 equation: 



6=(3x+1)2

We move all terms to the left:

6-((3x+1)2)=0



We calculate terms in parentheses: -((3x+1)2), so:

(3x+1)2

We multiply parentheses

6x+2

Back to the equation:

-(6x+2)



We get rid of parentheses

-6x-2+6=0

We add all the numbers together, and all the variables

-6x+4=0

We move all terms containing x to the left, all other terms to the right

-6x=-4

x=-4/-6

x=2/3

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