6=(1-x)+3(x+1)

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Solution for 6=(1-x)+3(x+1) equation: 



6=(1-x)+3(x+1)

We move all terms to the left:

6-((1-x)+3(x+1))=0

We add all the numbers together, and all the variables

-((-1x+1)+3(x+1))+6=0



We calculate terms in parentheses: -((-1x+1)+3(x+1)), so:

(-1x+1)+3(x+1)

We multiply parentheses

(-1x+1)+3x+3

We get rid of parentheses

-1x+3x+1+3

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We get rid of parentheses

-2x-4+6=0

We add all the numbers together, and all the variables

-2x+2=0

We move all terms containing x to the left, all other terms to the right

-2x=-2

x=-2/-2

x=1

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