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1/2(8x+26)=13+5x
We move all terms to the left:
1/2(8x+26)-(13+5x)=0
Domain of the equation: 2(8x+26)!=0We add all the numbers together, and all the variables
x∈R
1/2(8x+26)-(5x+13)=0
We get rid of parentheses
1/2(8x+26)-5x-13=0
We multiply all the terms by the denominator
-5x*2(8x+26)-13*2(8x+26)+1=0
Wy multiply elements
-10x^2(8-26x(8+1=0
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