-3(-6-4x)=8x+38

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Solution for -3(-6-4x)=8x+38 equation: 



-3(-6-4x)=8x+38

We move all terms to the left:

-3(-6-4x)-(8x+38)=0

We add all the numbers together, and all the variables

-3(-4x-6)-(8x+38)=0

We multiply parentheses

12x-(8x+38)+18=0

We get rid of parentheses

12x-8x-38+18=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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