4x-3(x-2)=5-2(x+3)

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Solution for 4x-3(x-2)=5-2(x+3) equation:



4x-3(x-2)=5-2(x+3)
We move all terms to the left:
4x-3(x-2)-(5-2(x+3))=0
We multiply parentheses
4x-3x-(5-2(x+3))+6=0
We calculate terms in parentheses: -(5-2(x+3)), so:
5-2(x+3)
determiningTheFunctionDomain -2(x+3)+5
We multiply parentheses
-2x-6+5
We add all the numbers together, and all the variables
-2x-1
Back to the equation:
-(-2x-1)
We add all the numbers together, and all the variables
x-(-2x-1)+6=0
We get rid of parentheses
x+2x+1+6=0
We add all the numbers together, and all the variables
3x+7=0
We move all terms containing x to the left, all other terms to the right
3x=-7
x=-7/3
x=-2+1/3

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